1810 Delaware gubernatorial election

← 1807 October 2, 1810 1813 →
 
Nominee Joseph Haslet Daniel Rodney
Party Democratic-Republican Federalist
Popular vote 3,664 3,593
Percentage 50.49% 49.51%

Governor before election

George Truitt
Federalist

Elected Governor

Joseph Haslet
Democratic-Republican

The 1810 Delaware gubernatorial election was held on October 2, 1810.

Incumbent Federalist Governor George Truitt was not eligible for re-election under the Delaware Constitution of 1792.

Democratic-Republican nominee Joseph Haslet defeated Federalist nominee Daniel Rodney with 50.49% of the vote.

General election

Results

1810 Delaware gubernatorial election[1][2][3][4]
Party Candidate Votes % ±%
Democratic-Republican Joseph Haslet 3,664 50.49%
Federalist Daniel Rodney 3,593 49.51%
Majority 71 0.98%
Turnout 7,257 100.00%
Democratic-Republican gain from Federalist Swing

References

  1. ^ "DE Governor, 1810". Our Campaigns. Retrieved December 8, 2020.
  2. ^ Congressional Quarterly 1998, p. 46.
  3. ^ Glashan 1979, pp. 50–51.
  4. ^ Dubin 2003, p. 26.

Bibliography