1856 United States presidential election in Indiana

← 1852 November 4, 1856 1860 →
 
Nominee James Buchanan John C. Frémont Millard Fillmore
Party Democratic Republican Know Nothing
Home state Pennsylvania California New York
Running mate John C. Breckinridge William L. Dayton Andrew J. Donelson
Electoral vote 13 0 0
Popular vote 118,670 94,375 22,386
Percentage 50.41% 40.09% 9.51%

President before election

Franklin Pierce
Democratic

Elected President

James Buchanan
Democratic

The 1856 United States presidential election in Indiana took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose 13 representatives, or electors to the Electoral College, who voted for president and vice president.

Indiana voted for the Democratic candidate, James Buchanan, over Republican candidate John C. Frémont and American Party candidate Millard Fillmore. Buchanan won Indiana by a margin of 10.32%.

A democratic presidential nominee would not win Indiana again until Samuel J. Tilden narrowly won it in 1876.

Results

1856 United States presidential election in Indiana[1][2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic James Buchanan of Pennsylvania John C. Breckinridge of Kentucky 118,670 50.41% 13 100.00%
Republican John C. Frémont of California William L. Dayton of New Jersey 94,375 40.09% 0 0.00%
Know Nothing Millard Fillmore of New York Andrew Jackson Donelson of Tennessee 22,386 9.51% 0 0.00%
Total 235,431 100.00% 13 100.00%

See also

References

  1. ^ "1856 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved 3 December 2017.
  2. ^ "1856 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 3 December 2017.