1868 United States presidential election in Arkansas

← 1860 November 3, 1868 1872 →
 
Nominee Ulysses S. Grant Horatio Seymour
Party Republican Democratic
Home state Illinois New York
Running mate Schuyler Colfax Francis Preston Blair, Jr.
Electoral vote 5 0
Popular vote 22,112 19,078
Percentage 53.68% 46.32%

President before election

Andrew Johnson
Democratic

Elected President

Ulysses S. Grant
Republican

The 1868 United States presidential election in Arkansas took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.

Arkansas voted for the Republican nominee, Ulysses S. Grant, over the Democratic nominee, Horatio Seymour. Grant won the state by a margin of 7.36%.

This was the first time since 1860 that a presidential election was held in the state due to secession, the American Civil War, and Reconstruction. This was also the first presidential election in which a Republican won Arkansas, which it would do next election, but would not do so again until over a century later when Richard Nixon carried the state in the 1972 election.

Results

1868 United States presidential election in Arkansas[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Ulysses S. Grant of Illinois Schuyler Colfax of Indiana 22,112 53.68% 5 100.00%
Democratic Horatio Seymour of New York Francis Preston Blair, Jr. of Missouri 19,078 46.32% 0 0.00%
Total 41,190 100.00% 5 100.00%

See also

References

  1. ^ "1868 Presidential General Election Results - Arkansas".