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Elections in Rhode Island |
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The 1879 Rhode Island gubernatorial election was held on April 2, 1879. Incumbent Republican Charles C. Van Zandt defeated Democratic nominee Thomas W. Segar with 62.09% of the vote.
Major party candidates
Other candidates
Party | Candidate | Votes | % | ±% | |
---|---|---|---|---|---|
Republican | Charles C. Van Zandt (incumbent) | 9,717 | 62.09% | ||
Democratic | Thomas W. Segar | 5,506 | 35.18% | ||
Greenback | Samuel Hill | 318 | 2.03% | ||
Majority | 4,211 | ||||
Turnout | |||||
Republican hold | Swing |