1884 United States presidential election in Indiana

← 1880 November 4, 1884 1888 →
 
StephenGroverCleveland.png
Unsuccessful 1884.jpg
Nominee Grover Cleveland James G. Blaine
Party Democratic Republican
Home state New York Maine
Running mate Thomas A. Hendricks John A. Logan
Electoral vote 15 0
Popular vote 245,005 238,489
Percentage 49.46% 48.15%

Indiana Presidential Election Results 1884.svg
County Results

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

The 1884 United States presidential election in Indiana took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for president and vice president.

Indiana voted for the Democratic nominee, Grover Cleveland over the Republican nominee, James G. Blaine. Cleveland won the state by a narrow margin of 1.31%.

Results

1884 United States presidential election in Indiana[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Grover Cleveland of New York Thomas Andrews Hendricks of Indiana 245,005 49.46% 15 100.00%
Republican James Gillespie Blaine of Maine John Alexander Logan of Illinois 238,489 48.15% 0 0.00%
Greenback Benjamin Franklin Butler of Massachusetts Absolom Madden West of Mississippi 8,810 1.78% 0 0.00%
Prohibition John Pierce St. John of Kansas William Daniel of Maryland 3,028 0.61% 0 0.00%
Total 495,332 100.00% 15 100.00%

See also

References

  1. ^ "1884 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved 23 December 2013.