The 1892 United States House of Representatives elections were held for the most part on November 8, 1892, with Oregon, Maine, and Vermont holding theirs early in either June or September. They coincided with the election of Grover Cleveland as president for the second, non-continuous, time, defeating incumbent Benjamin Harrison. Elections were held for 356 seats of the United States House of Representatives, representing 44 states, to serve in the 53rd United States Congress. They were the first elections after reapportionment following the 1890 United States census, increasing the size of the House. Special elections were also held throughout the year.
In spite of the presidential results, Harrison's Republican Party gained back some of the seats that had been lost in 1890 to the Democratic Party, but was still deep in the minority. The Republican pickups were a result of a number of Republican-friendly Northern districts reverting to form after voting Democratic in the previous election cycle. The third party Populists, who had high support among farmers and laborers in the South and West, also gained three seats.
Election summaries
This was the first election after reapportionment following the 1890 census. Twenty-four new seats were added,[2] with 13 States gaining one seat each, two States gaining 2 seats each, and one state gaining 3 seats, and the remaining 28 states having no change. Several states did not redistrict following the apportionment of extra seats, and elected those new seats at-large.
One new seat was added in reapportionment. Populists had a net gain of two seats, one taken from the Republicans, the other being a seat in the new district.
^ abcdThree states held early elections between June 6 and September 12, and Rhode Island had a late run-off election April 5, 1893.
^ abDubin (p. 303) records 214 Democrats, 2 Independent Democrats, 127 Republicans, 11 Populists, and 1 Silver at the opening of the 53rd Congress, before several contested elections overturned a few results.
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