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29 out of 50 seats in the Iowa Senate 26 seats needed for a majority | ||||||||||||||||
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 Results Democratic gain Republican gain Democratic hold Republican hold | ||||||||||||||||
| Elections in Iowa |
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The 1908 Iowa Senate elections took place as part of the biennial 1908 United States elections. Iowa voters elected state senators in 29 of the senate's 50 districts. State senators serve four-year terms in the Iowa Senate.
A statewide map of the 50 state Senate districts in the 1908 elections is provided by the Iowa General Assembly here.
The 1908 elections were the first in Iowa with primary elections due to the enactment of the Primary Election Law by the General Assembly in 1907.[1] The primary election on June 2, 1908, determined which candidates appeared on the November 3, 1908 general election ballot.[2][3]
Following the previous election, Republicans had control of the Iowa Senate with 36 seats to Democrats' 14 seats.
To claim control of the chamber from Republicans, the Democrats needed to net 12 Senate seats.
Republicans maintained control of the Iowa State Senate following the 1908 general election with the balance of power shifting to Republicans holding 34 seats and Democrats having 16 seats (a net gain of 2 seats for Democrats).
