1908 United States presidential election in Indiana

← 1904 November 3, 1908 1912 →
 
Nominee William Howard Taft William Jennings Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate James S. Sherman John W. Kern
Electoral vote 15 0
Popular vote 348,993 338,262
Percentage 48.40% 46.91%

County Results

President before election

Theodore Roosevelt
Republican

Elected President

William Howard Taft
Republican

The 1908 United States presidential election in Indiana took place on November 3, 1908. Voters chose 15 representatives, or electors to the Electoral College, who voted for president and vice president.

Indiana voted for the Republican nominee, Secretary of War William Howard Taft, over the Democratic nominee, former U.S. Representative William Jennings Bryan. Taft won the state by a narrow margin of 1.49%.

Results

1908 United States presidential election in Indiana[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican William Howard Taft of Ohio James Schoolcraft Sherman of New York 348,993 48.40% 15 100.00%
Democratic William Jennings Bryan of Nebraska John Worth Kern of Indiana 338,262 46.91% 0 0.00%
Prohibition Eugene Wilder Chafin of Illinois Aaron Sherman Watkins of Ohio 18,845 2.50% 0 0.00%
Socialist Eugene Victor Debs of Indiana Benjamin Hanford of New York 13,476 1.87% 0 0.00%
Populist Thomas Edward Watson of Georgia Samuel Williams of Indiana 1,193 0.17% 0 0.00%
Socialist Labor August Gillhaus of New York Donald L. Munro of Virginia 643 0.09% 0 0.00%
Independence Thomas Louis Hisgen of Massachusetts John Temple Graves of Georgia 514 0.07% 0 0.00%
Total 721,126 100.00% 15 100.00%

See also

References

  1. ^ "1908 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved 23 December 2013.