The UEFA European Under-18 Championship 1956 Final Tournament was held in Hungary. During this edition, only group matches were played and no winner was declared. This was done to prevent an excess of competition. Hungary, Italy, Romania and Czechoslovakia were the four group winners.

Teams

The following teams entered the tournament:

•  Austria
•  Belgium
•  Bulgaria
•  Czechoslovakia
•  East Germany
•  England
•  France
•  West Germany
•  Greece
•  Hungary (host)
•  Italy
•  Poland
•  Romania
•  Saar
•  Turkey
•  Yugoslavia

Group A

Teams	Pld	W	D	L	GF	GA	GD	Pts
Hungary	3	2	1	0	6	3	+3	5
West Germany	3	1	1	1	2	2	0	3
Bulgaria	3	1	0	2	3	4	–1	2
England	3	1	0	2	5	7	–2	2

28 March	Hungary	0–0	West Germany
	Bulgaria	2–1	England
30 March	West Germany	1–0	Bulgaria
	Hungary	4–2	England
1 April	Hungary	2–1	Bulgaria
	England	2–1	West Germany

Group B

Teams	Pld	W	D	L	GF	GA	GD	Pts
Italy	3	2	0	1	5	2	+3	4
France	3	2	0	1	4	3	+1	4
Saar	3	1	1	1	3	5	–2	3
Belgium	3	0	1	2	5	7	–2	1

28 March	Saar	1–0	France
	Italy	2–1	Belgium
30 March	France	3–2	Belgium
	Italy	3–0	Saar
1 April	Saar	2–2	Belgium
	France	1–0	Italy

Group C

Teams	Pld	W	D	L	GF	GA	GD	Pts
Romania	3	2	1	0	6	2	+4	5
Poland	3	1	1	1	4	4	0	3
Yugoslavia	3	0	2	1	2	3	–1	2
Austria	3	1	0	2	4	7	–3	2

29 March	Romania	1–1	Yugoslavia
	Poland	3–2	Austria
31 March	Austria	1–0	Yugoslavia
	Romania	1–0	Poland
2 April	Romania	4–1	Austria
	Poland	1–1	Yugoslavia

Group D

Teams	Pld	W	D	L	GF	GA	GD	Pts
Czechoslovakia	3	2	1	0	4	1	+3	5
Turkey	3	1	1	1	4	2	+2	3
East Germany	3	0	3	0	3	3	0	3
Greece	3	0	1	2	1	6	–5	1

29 March	Czechoslovakia	2–0	Greece
	East Germany	1–1	Turkey
31 March	Czechoslovakia	1–1	East Germany
	Turkey	3–0	Greece
2 April	Czechoslovakia	1–0	Turkey
	East Germany	1–1	Greece