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 County Results
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| Elections in Wyoming |
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The 1956 United States presidential election in Wyoming took place on November 6, 1956, as part of the 1956 United States presidential election. State voters chose three[4] representatives, or electors, to the Electoral College, who voted for president and vice president.
Wyoming was won by incumbent President Dwight D. Eisenhower (R–Pennsylvania), running with Vice President Richard Nixon, with 60.08 percent of the popular vote, against Adlai Stevenson (D–Illinois), running with Senator Estes Kefauver, with 39.92 percent of the popular vote, a Republican victory margin of 20.2%.[5][6] This margin represented a slight decrease from Eisenhower's victory in the state 4 years earlier in 1952, despite the fact that he won nationwide by a larger margin. Nevertheless, Wyoming still weighed in as 2.8% more Republican than the rest of the nation. Ironically enough, despite his margins in most of the counties he won being slightly less than 1952, Eisenhower was able to improve upon his margins in the heavily unionized Sweetwater County, with the area swinging to the right by 6.7%, making him the first Republican to break 40% of the county's vote since Herbert Hoover in 1928.
Eisenhower's underperformance relative to 1952 was not unique to just Wyoming, as most of the Mountain West swung a few points against him. Given the fact that the state's economy relied heavily upon agriculture, this is possibly due to a 5 year long drought in the High Plains, which encompasses parts of Wyoming, Montana, Colorado, and New Mexico.[7]
This would be the last time that Wyoming would give 60% or more of its vote to any candidate until Richard Nixon's 1972 landslide victory, and the last time that Carbon and Laramie counties would select the Republican nominee until 1968 and 1972, respectively. This election was the first time ever that a Republican won two presidential terms by carrying Wyoming in both instances.
