1976 edition of the Federation Cup
1976 Federation Cup|
| Duration | 22–29 August |
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| Edition | 14th |
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| Winning Nation |  United States |
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The 1976 Federation Cup was the 14th edition of the most important competition between national teams in women's tennis. For the first time, enough teams entered to necessitate pre-qualifying rounds. The tiebreaker also was used for the first time. The tournament was held at The Spectrum in Philadelphia, United States, from 22 to 29 August. The United States defeated Australia in the final, in what was the sixth final between United States and Australia.
Qualifying round
Eight nations played off in July for a place in the main draw.
Luxembourg, Mexico, Philippines, and Switzerland advanced to Main Draw.
Main draw
All ties were played at The Spectrum in Philadelphia, United States, on indoor carpet courts.
1st Round losing teams play in Consolation Rounds
First round
Indonesia vs. Switzerland
[1]
Norway vs. Yugoslavia
[2]
Israel vs. United States
[3]
New Zealand vs. Argentina
[4]
Brazil vs. Netherlands
[5]
Denmark vs. Spain
[6]
France vs. Great Britain
[7]
Hungary vs. Philippines
[8]
Sweden vs. Japan
[9]
South Korea vs. South Africa
[10]
Italy vs. Luxembourg
[11]
Mexico vs. West Germany
[12]
Belgium vs. Rhodesia
[13]
Romania vs. Australia
[14]
Second round
Canada vs. Switzerland
[15]
Yugoslavia vs. United States
[16]
Argentina vs. Netherlands
[17]
Denmark vs. Uruguay
[18]
Sweden vs. South Africa
[19]
Italy vs. West Germany
[20]
Belgium vs. Australia
[21]
Quarterfinals
Switzerland vs. United States
[22]
Netherlands vs. Denmark
[23]
Great Britain vs. South Africa
[24]
West Germany vs. Australia
[25]
Semifinals
United States vs. Netherlands
[26]
Great Britain vs. Australia
[27]
Final
United States vs. Australia
[28]
| 1976 Federation Cup Champions
|
United States
Fifth title
|
