| CONCACAF Championship | |
|---|---|
| Tournament details | |
| Host country | United States |
| Dates | February 1–15 |
| Teams | 10 (from 2 confederations) |
| Venue(s) | 3 (in 3 host cities) |
| Final positions | |
| Champions |  Mexico (3rd title) |
| Runners-up |  United States |
| Third place |  Brazil |
| Fourth place |  Jamaica |
| Tournament statistics | |
| Matches played | 16 |
| Goals scored | 44 (2.75 per match) |
| Top scorer(s) | Luis Hernández Paulo Wanchope(4 goals each) |
| Best player(s) | Kasey Keller |
The 1998 CONCACAF Gold Cup was the fourth edition of the Gold Cup, the soccer championship for the member associations of CONCACAF, which governs the sport in North America, Central America, and the Caribbean.
The tournament was once again held in the United States, with matches played in Los Angeles, Miami, and Oakland, California. The format of the tournament changed from 1996: it was expanded to ten teams, with four in Group A and three each in Groups B and C. The top team in each group, plus the second place in Group A would advance to the semifinals. Brazil was invited again, and brought their senior team this time. Prior to the tournament, Canada withdrew due to a lack of available players and were replaced by Jamaica.[1]
Jamaica topped Group A over Brazil, who they tied 0–0, in a surprise result for the team. In the semi-finals, the United States beat Brazil, as Preki scored the lone goal and Kasey Keller preserved the clean sheet. The United States could not repeat that performance in front of a pro-Mexican final crowd in Los Angeles. Mexico won their third straight Gold Cup, 1–0, on a Luis Hernández goal.
