Dipole field strength in free space, in telecommunications, is the electric field strength caused by a half wave dipole under ideal conditions. The actual field strength in terrestrial environments is calculated by empirical formulas based on this field strength.

Power density

Let N be the effective power radiated from an isotropic antenna and p be the power density at a distance d from this source^[1]

${\displaystyle {\mbox{p))={\frac {N}{4\cdot \pi \cdot d^{2))))$

Power density is also defined in terms of electrical field strength;

Let E be the electrical field and Z be the impedance of the free space

${\displaystyle {\mbox{p))={\frac {E^{2)){Z))}$

The following relation is obtained by equating the two,

${\displaystyle {\frac {N}{4\cdot \pi \cdot d^{2))}={\frac {E^{2)){Z))}$

or by rearranging the terms

${\displaystyle {\mbox{E))={\frac ((\sqrt {N))\cdot {\sqrt {Z))}{2\cdot {\sqrt {\pi ))\cdot d))}$

Numerical values

Impedance of free space is roughly ${\displaystyle 120\cdot \pi }$

Since a half wave dipole is used, its gain over an isotropic antenna (${\displaystyle {\mbox{2.15 dBi))=1.64}$ ) should also be taken into consideration,

${\displaystyle {\mbox{E))={\frac ((\sqrt {1.64\cdot N))\cdot {\sqrt {120\cdot \pi ))}{2\cdot {\sqrt {\pi ))\cdot d))\approx 7\cdot {\frac {\sqrt {N)){d))}$

In this equation SI units are used.

Expressing the same equation in:

kW instead of W in power,

km instead of m in distance and

mV/m instead of V/m in electric field

is equivalent to multiplying the expression on the right by ${\displaystyle {\sqrt {1000))}$.^[2] In this case,

${\displaystyle {\mbox{E))\approx 222\cdot {\frac {\sqrt {N)){d))}$