In chemical kinetics, the entropy of activation of a reaction is one of the two parameters (along with the enthalpy of activation) which are typically obtained from the temperature dependence of a reaction rate constant, when these data are analyzed using the Eyring equation of the transition state theory. The standard entropy of activation is symbolized ΔS^‡ and equals the change in entropy when the reactants change from their initial state to the activated complex or transition state (Δ = change, S = entropy, ‡ = activation).

Importance

Entropy of activation determines the preexponential factor A of the Arrhenius equation for temperature dependence of reaction rates. The relationship depends on the molecularity of the reaction:

• for reactions in solution and unimolecular gas reactions

A = (ek_BT/h) exp(ΔS^‡/R),

• while for bimolecular gas reactions

A = (e²k_BT/h) (RT/p) exp(ΔS^‡/R).

In these equations e is the base of natural logarithms, h is the Planck constant, k_B is the Boltzmann constant and T the absolute temperature. R' is the ideal gas constant in units of (bar·L)/(mol·K). The factor is needed because of the pressure dependence of the reaction rate. R' = 8.3145 × 10⁻² (bar·L)/(mol·K).^[1]

The value of ΔS^‡ provides clues about the molecularity of the rate determining step in a reaction, i.e. the number of molecules that enter this step.^[2] Positive values suggest that entropy increases upon achieving the transition state, which often indicates a dissociative mechanism in which the activated complex is loosely bound and about to dissociate. Negative values for ΔS^‡ indicate that entropy decreases on forming the transition state, which often indicates an associative mechanism in which two reaction partners form a single activated complex.^[3]

Derivation

It is possible to obtain entropy of activation using Eyring equation. This equation is of the form

$${\displaystyle k={\frac {\kappa k_{\mathrm {B} }T}{h))e^{\frac {\Delta S^{\ddagger )){R))e^{-{\frac {\Delta H^{\ddagger )){RT))))$$

• ${\displaystyle k}$ = reaction rate constant
• ${\displaystyle T}$ = absolute temperature
• ${\displaystyle \Delta H^{\ddagger ))$ = enthalpy of activation
• ${\displaystyle R}$ = gas constant
• ${\displaystyle \kappa }$ = transmission coefficient
• ${\displaystyle k_{\mathrm {B} ))$ = Boltzmann constant = R/N_A, N_A = Avogadro constant
• ${\displaystyle h}$ = Planck's constant
• ${\displaystyle \Delta S^{\ddagger ))$ = entropy of activation

This equation can be turned into the form

$${\displaystyle \ln {\frac {k}{T))={\frac {-\Delta H^{\ddagger )){R))\cdot {\frac {1}{T))+\ln {\frac {\kappa k_{\mathrm {B} )){h))+{\frac {\Delta S^{\ddagger )){R))}$$

${\displaystyle \ln(k/T)}$

${\displaystyle 1/T}$

${\displaystyle -\Delta H^{\ddagger }/R}$

${\displaystyle \ln(\kappa k_{\mathrm {B} }/h)+\Delta S^{\ddagger }/R}$