Town in Wisconsin, United States
Lafayette is a town in Monroe County, Wisconsin, United States. The population was 318 at the 2000 census.
Geography
According to the United States Census Bureau, the town has a total area of 35.3 square miles (91.5 km2), of which, 35.3 square miles (91.4 km2) of it is land and 0.04 square miles (0.1 km2) of it (0.11%) is water.
Demographics
As of the census[2] of 2000, there were 318 people, 106 households, and 75 families residing in the town. The population density was 9.0 people per square mile (3.5/km2). There were 126 housing units at an average density of 3.6 per square mile (1.4/km2). The racial makeup of the town was 95.91% White, 1.89% African American, 0.31% Native American, 0.31% Asian, 0.31% Pacific Islander, 1.26% from other races. Hispanic or Latino of any race were 2.52% of the population.
There were 106 households, out of which 31.1% had children under the age of 18 living with them, 64.2% were married couples living together, 3.8% had a female householder with no husband present, and 29.2% were non-families. 24.5% of all households were made up of individuals, and 3.8% had someone living alone who was 65 years of age or older. The average household size was 2.53 and the average family size was 3.05.
In the town, the population was spread out, with 21.4% under the age of 18, 8.8% from 18 to 24, 35.2% from 25 to 44, 26.1% from 45 to 64, and 8.5% who were 65 years of age or older. The median age was 38 years. For every 100 females, there were 128.8 males. For every 100 females age 18 and over, there were 140.4 males.
The median income for a household in the town was $35,417, and the median income for a family was $40,000. Males had a median income of $25,833 versus $21,667 for females. The per capita income for the town was $16,506. About 3.9% of families and 6.0% of the population were below the poverty line, including 4.9% of those under age 18 and none of those age 65 or over.
United States
Wisconsin