Seymour Lake
Location of lake in Vermont.
Location of lake in Vermont.
Seymour Lake
LocationOrleans County, Vermont
Coordinates44°53′46″N 71°59′13″W / 44.896°N 71.987°W / 44.896; -71.987
Typelake
Surface area1,777.3 acres (7.192 km2)
Max. depth181.5 feet (55.3 m)
Water volume5,565,106,923 cubic feet (157,586,279.0 m3)

Seymour Lake is a spring-fed lake located in Morgan, Vermont, which is located in the Northeast Kingdom of Vermont. The lake is on a tributary of the Clyde River in Orleans County, Vermont. The lake, which was completed in 1928, is 2.8 square miles and the surface area is 1,777.3 acres (7.192 km2). The elevation is 1280.5 feet.

The closest major airport is located in Burlington, Vermont, located approximately 101 miles away.

Environment

Historically the lake had a population of Rainbow smelt, which is absent as of 2021.[1]

Phosphorus levels had been increasing in the lake, but are now kept stable.[2]

References

  • Findlakes.com. "Findlakes.com". Retrieved 1 September 2011.
  • Vermont Water Quality Division. "Water Quality Division" (PDF). Retrieved 3 December 2023.
  1. ^ "Seymour Lake: Where did all the smelt go?". Barton Chronicle Newspaper. 26 May 2021. Retrieved 30 November 2021.
  2. ^ "Vermont's 'Jewels' Under Threat: Clearest, Cleanest Lakes Face Phosphorus Pollution". Vermont Public Radio. 5 August 2019. Retrieved 30 November 2021.
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