(({1))}
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This template uses Lua: |
This template removes the last word of the first parameter, i.e. the last non-space token after the last space. Use |1=
for the first parameter if the string may contain an equals sign (=). By default, words are delimited by spaces, but the optional parameter |sep=
can set the separator to any character.
One parameter (space as separator):
((Remove last word|string))
((Remove last word|1=string))
Two parameters (user-defined character as separator):
((Remove last word|string|sep=character))
((Remove last word|1=string|sep=character))
((Remove last word|Remove last word))
→ Remove last((Remove last word|Remove last))
→ Remove((Remove last word|Remove))
→ Remove((Remove last word|Remove, last word|sep=,))
→ Remove((Remove last word|Foo-bar|sep=-))
→ Foo((Remove last word|1=len = a+b|sep==))
→ len