Warrensville Heights, Ohio | |
---|---|
Motto: "The Friendly City" | |
![]() Location in Cuyahoga County and the state of Ohio | |
![]() Location of Ohio in the United States | |
Coordinates: 41°26′19″N 81°31′24″W / 41.43861°N 81.52333°W | |
Country | United States |
State | Ohio |
County | Cuyahoga |
Village incorporated | 1927 [1] |
Incorporated | 1960 [1] |
Government | |
• Type | Mayor-council |
• Mayor | Brad Sellers (D) |
Area | |
• Total | 4.14 sq mi (10.72 km2) |
• Land | 4.13 sq mi (10.70 km2) |
• Water | 0.01 sq mi (0.03 km2) 0.24% |
Elevation | 1,037 ft (316 m) |
Population (2010) | |
• Total | 13,542 |
• Estimate (2018[2]) | 13,216 |
• Density | 3,278.9/sq mi (1,266.0/km2) |
census | |
Time zone | UTC-5 (EST) |
• Summer (DST) | UTC-4 (EDT) |
Zip code | 44122, 44128 |
Area code | 216 |
FIPS code | 39-80990[3] |
GNIS feature ID | 1047579[4] |
Website | http://www.cityofwarrensville.com/ |
Warrensville Heights is a city located in Cuyahoga County, Ohio, United States. It is an East Side suburb of Cleveland. The population was 13,542 at the 2010 U.S. Census.