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The 1870 Rhode Island gubernatorial election took place on April 6, 1870 in order to elect the governor of Rhode Island.[1] Republican candidate and incumbent governor Seth Padelford won his second one-year term as governor[2] over Democratic candidate Lyman Pierce.[3]
Party | Candidate | Votes | % | |
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Republican | Seth Padelford | 10,337 | 62.15 | |
Democratic | Lyman Pierce | 6,295 | 37.85 | |
Total votes | 16,632 | 100.00 | ||
Republican hold |
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