${\displaystyle {\pi }_{5))$

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$\sum _{k=1}^{\infty }{\frac {1}{x^{k))}={\frac {1}{x-1)),x>1$

It subsequently follows that

$\sum _{k=0}^{\infty }{\frac {1}{x^{k))}=1+{\frac {1}{x-1)),x>1$

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${\displaystyle log_{5}{\sqrt[{e}]{\pi ^{\pi ))}+\sum _{k={\sqrt {2))}^{\infty }{\frac {\pi }{k!))+\prod _{k={\sqrt[{\pi }]{529))}^{\infty }log_{k}{\sqrt[{k}]{426_{k))}=\lim _{n\to \infty }(n+{\sqrt[{n}]{n)))^{\infty ))$

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This is school-related $((\sqrt ((X^{2}-2X+1} \over {X+2{\sqrt {X))+1))}+((X^{3}+3X^{2}+3X+1} \over {X^{2}+2X+1))} \over ((\sqrt ((X^{3}-X} \over {X^{2}-X))}+((X-2{\sqrt {2X))+1} \over {-({\sqrt {X))-{\sqrt {2)))^{2))))$

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