2023 World Snooker Championship

2023 World Snooker Championship (edit | talk | history | links | watch | logs)

As of 20 February 2024, 21:02 (UTC), this page is active and open for discussion. An FAC coordinator will be responsible for closing the nomination.

Nominator(s): Lee Vilenski (talkcontribs) 11:01, 30 January 2024 (UTC), User:HurricaneHigginsReply[reply]

This article is about the annual FAC for the main snooker tournament of the year. A bit later than usual as the GAN took a while to get looked at. Let me know your thoughts. Lee Vilenski (talkcontribs) 11:01, 30 January 2024 (UTC)Reply[reply]

Image review

Comments from BennyOntheLoose

To my surprise, I'm listed as 2nd on the authorship list for this article; this is almost entirely due to me running IABot on it. Co-ords, please let me know whether it would be appropriate for me to express a "vote" on this one. BennyOnTheLoose (talk) 23:12, 15 February 2024 (UTC)Reply[reply]

Thank you @BennyOnTheLoose. I've tried to address your comments by shortening the lead to three paragraphs and under 400 words. I've also addressed your concerns about references #5, #24, #30, and #184, and have inserted Dave Hendon as the correct author of the article you noted. I also attributed that quote to Calladine.
Agreed that World Snooker articles are used frequently as a source, but they are accurate when it comes to scores, match summaries, post-match quotes from players, and other factual information, and would suggest that relying on this information does not introduce any bias into the article itself. As for using Metro, I'd note that the cited articles were written by the respected snooker journalist Phil Haigh, co-host of the Talking Snooker podcast with Nick Metcalfe, and might request that they be allowed here on the basis of Haigh being an established and reputable commentator on the sport.
I did not work on the Main Draw section, and might request those who did to address your concerns with references. HurricaneHiggins (talk) 12:43, 19 February 2024 (UTC)Reply[reply]