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1884 United States presidential election in Louisiana

← 1880 November 4, 1884 1888 →
 
StephenGroverCleveland.jpg
Unsuccessful 1884.jpg
Nominee Grover Cleveland James G. Blaine
Party Democratic Republican
Home state New York Maine
Running mate Thomas A. Hendricks John A. Logan
Electoral vote 7 0
Popular vote 62,594 46,347
Percentage 57.22% 42.37%

Louisiana Presidential Election Results 1884.svg
Parish Results

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

The 1884 United States presidential election in Louisiana took place on November 4, 1884. All contemporary 38 states were part of the 1884 United States presidential election. State voters chose eight electors to the Electoral College, which selected the president and vice president.

Louisiana voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine by a margin of 14.85%.

Results

1884 United States presidential election in Louisiana[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Grover Cleveland of New York Thomas Andrews Hendricks of Indiana 62,594 57.22% 8 100.00%
Republican James Gillespie Blaine of Maine John Alexander Logan of Illinois 46,347 42.37% 0 0.00%
Prohibition John Pierce St. John of Kansas William Daniel of Maryland 338 0.31% 0 0.00%
Greenback Benjamin Franklin Butler of Massachusetts Absolom Madden West of Mississippi 120 0.11% 0 0.00%
Total 109,399 100.00% 8 100.00%

See also

References

  1. ^ "1884 Presidential General Election Results - Louisiana". U.S. Election Atlas. Retrieved November 25, 2020.