Infinitesimal strain tensor
For infinitesimal deformations of a continuum body, in which the displacement gradient (2nd order tensor) is small compared to unity, i.e. ,
it is possible to perform a geometric linearization of any one of the (infinitely many possible) strain tensors used in finite strain theory, e.g. the Lagrangian strain tensor , and the Eulerian strain tensor . In such a linearization, the non-linear or second-order terms of the finite strain tensor are neglected. Thus we have
This linearization implies that the Lagrangian description and the Eulerian description are approximately the same as there is little difference in the material and spatial coordinates of a given material point in the continuum. Therefore, the material displacement gradient components and the spatial displacement gradient components are approximately equal. Thus we have
where are the components of the infinitesimal strain tensor , also called Cauchy's strain tensor, linear strain tensor, or small strain tensor.
or using different notation:
Furthermore, since the deformation gradient can be expressed as where is the second-order identity tensor, we have
Also, from the general expression for the Lagrangian and Eulerian finite strain tensors we have
Figure 1. Two-dimensional geometric deformation of an infinitesimal material element.
Consider a two-dimensional deformation of an infinitesimal rectangular material element with dimensions by (Figure 1), which after deformation, takes the form of a rhombus. From the geometry of Figure 1 we have
For very small displacement gradients, i.e., , we have
The normal strain in the -direction of the rectangular element is defined by
and knowing that , we have
Similarly, the normal strain in the -direction, and -direction, becomes
The engineering shear strain, or the change in angle between two originally orthogonal material lines, in this case line and , is defined as
From the geometry of Figure 1 we have
For small rotations, i.e. and are we have
and, again, for small displacement gradients, we have
By interchanging and and and , it can be shown that
Similarly, for the - and - planes, we have
It can be seen that the tensorial shear strain components of the infinitesimal strain tensor can then be expressed using the engineering strain definition, , as
From finite strain theory we have
For infinitesimal strains then we have
Dividing by we have
For small deformations we assume that , thus the second term of the left hand side becomes: .
Then we have
where , is the unit vector in the direction of , and the left-hand-side expression is the normal strain in the direction of . For the particular case of in the direction, i.e. , we have
Similarly, for and we can find the normal strains and , respectively. Therefore, the diagonal elements of the infinitesimal strain tensor are the normal strains in the coordinate directions.
Strain transformation rules
If we choose an orthonormal coordinate system () we can write the tensor in terms of components with respect to those base vectors as
In matrix form,
We can easily choose to use another orthonormal coordinate system () instead. In that case the components of the tensor are different, say
The components of the strain in the two coordinate systems are related by
where the Einstein summation convention for repeated indices has been used and . In matrix form
Certain operations on the strain tensor give the same result without regard to which orthonormal coordinate system is used to represent the components of strain. The results of these operations are called strain invariants. The most commonly used strain invariants are
In terms of components
It can be shown that it is possible to find a coordinate system () in which the components of the strain tensor are
The components of the strain tensor in the () coordinate system are called the principal strains and the directions are called the directions of principal strain. Since there are no shear strain components in this coordinate system, the principal strains represent the maximum and minimum stretches of an elemental volume.
If we are given the components of the strain tensor in an arbitrary orthonormal coordinate system, we can find the principal strains using an eigenvalue decomposition determined by solving the system of equations
This system of equations is equivalent to finding the vector along which the strain tensor becomes a pure stretch with no shear component.
The dilatation (the relative variation of the volume) is the first strain invariant or trace of the tensor:
Actually, if we consider a cube with an edge length a, it is a quasi-cube after the deformation (the variations of the angles do not change the volume) with the dimensions and V0 = a3, thus
as we consider small deformations,
therefore the formula.
Real variation of volume (top) and the approximated one (bottom): the green drawing shows the estimated volume and the orange drawing the neglected volume
In case of pure shear, we can see that there is no change of the volume.
Strain deviator tensor
The infinitesimal strain tensor , similarly to the Cauchy stress tensor, can be expressed as the sum of two other tensors:
- a mean strain tensor or volumetric strain tensor or spherical strain tensor, , related to dilation or volume change; and
- a deviatoric component called the strain deviator tensor, , related to distortion.
where is the mean strain given by
The deviatoric strain tensor can be obtained by subtracting the mean strain tensor from the infinitesimal strain tensor:
Let () be the directions of the three principal strains. An octahedral plane is one whose normal makes equal angles with the three principal directions. The engineering shear strain on an octahedral plane is called the octahedral shear strain and is given by
where are the principal strains.
The normal strain on an octahedral plane is given by
A scalar quantity called the equivalent strain, or the von Mises equivalent strain, is often used to describe the state of strain in solids. Several definitions of equivalent strain can be found in the literature. A definition that is commonly used in the literature on plasticity is
This quantity is work conjugate to the equivalent stress defined as
Infinitesimal rotation tensor
The infinitesimal strain tensor is defined as
Therefore the displacement gradient can be expressed as
The quantity is the infinitesimal rotation tensor. This tensor is skew symmetric. For infinitesimal deformations the scalar components of satisfy the condition . Note that the displacement gradient is small only if both the strain tensor and the rotation tensor are infinitesimal.
The axial vector
A skew symmetric second-order tensor has three independent scalar components. These three components are used to define an axial vector, , as follows
where is the permutation symbol. In matrix form
The axial vector is also called the infinitesimal rotation vector. The rotation vector is related to the displacement gradient by the relation
In index notation
If and then the material undergoes an approximate rigid body rotation of magnitude around the vector .
Relation between the strain tensor and the rotation vector
Given a continuous, single-valued displacement field and the corresponding infinitesimal strain tensor , we have (see Tensor derivative (continuum mechanics))
Since a change in the order of differentiation does not change the result, . Therefore
Relation between rotation tensor and rotation vector
From an important identity regarding the curl of a tensor we know that for a continuous, single-valued displacement field ,
Since we have