provided that the limit exists for all , where the limit is taken for scalar . This is similar to the usual definition of a directional derivative but extends it to functions that are not necessarily scalar-valued.
Next, choose a set of basis vectors and consider the operators, denoted , that perform directional derivatives in the directions of :
where the geometric product is applied after the directional derivative. More verbosely:
This operator is independent of the choice of frame, and can thus be used to define what in geometric calculus is called the vector derivative:
This is similar to the usual definition of the gradient, but it, too, extends to functions that are not necessarily scalar-valued.
The directional derivative is linear regarding its direction, that is:
From this follows that the directional derivative is the inner product of its direction by the vector derivative. All needs to be observed is that the direction can be written , so that:
For this reason, is often noted .
The standard order of operations for the vector derivative is that it acts only on the function closest to its immediate right. Given two functions and , then for example we have
Although the partial derivative exhibits a product rule, the vector derivative only partially inherits this property. Consider two functions and :
Since the geometric product is not commutative with in general, we need a new notation to proceed. A solution is to adopt the overdot notation, in which the scope of a vector derivative with an overdot is the multivector-valued function sharing the same overdot. In this case, if we define
then the product rule for the vector derivative is
Interior and exterior derivative
Let be an -grade multivector. Then we can define an additional pair of operators, the interior and exterior derivatives,
In particular, if is grade 1 (vector-valued function), then we can write
Unlike the vector derivative, neither the interior derivative operator nor the exterior derivative operator is invertible.
The derivative with respect to a vector as discussed above can be generalized to a derivative with respect to a general multivector, called the multivector derivative.
Let be a multivector-valued function of a multivector. The directional derivative of with respect to in the direction , where and are multivectors, is defined as
where is the scalar product. With a vector basis and the corresponding dual basis, the multivector derivative is defined in terms of the directional derivative as
where is denoting an ordered set of basis vector indices, as in the article section Geometric algebra#Dual basis. This equation is just expressing in terms of components in a reciprocal basis of blades, as discussed in that article section.
A key property of the multivector derivative is that
where is the projection of onto the grades contained in .
Let be a set of basis vectors that span an -dimensional vector space. From geometric algebra, we interpret the pseudoscalar to be the signed volume of the -parallelotope subtended by these basis vectors. If the basis vectors are orthonormal, then this is the unit pseudoscalar.
More generally, we may restrict ourselves to a subset of of the basis vectors, where , to treat the length, area, or other general -volume of a subspace in the overall -dimensional vector space. We denote these selected basis vectors by . A general -volume of the -parallelotope subtended by these basis vectors is the grade multivector .
Even more generally, we may consider a new set of vectors proportional to the basis vectors, where each of the is a component that scales one of the basis vectors. We are free to choose components as infinitesimally small as we wish as long as they remain nonzero. Since the outer product of these terms can be interpreted as a -volume, a natural way to define a measure is
The measure is therefore always proportional to the unit pseudoscalar of a -dimensional subspace of the vector space. Compare the Riemannian volume form in the theory of differential forms. The integral is taken with respect to this measure:
More formally, consider some directed volume of the subspace. We may divide this volume into a sum of simplices. Let be the coordinates of the vertices. At each vertex we assign a measure as the average measure of the simplices sharing the vertex. Then the integral of with respect to over this volume is obtained in the limit of finer partitioning of the volume into smaller simplices:
Fundamental theorem of geometric calculus
The reason for defining the vector derivative and integral as above is that they allow a strong generalization of Stokes' theorem. Let be a multivector-valued function of -grade input and general position , linear in its first argument. Then the fundamental theorem of geometric calculus relates the integral of a derivative over the volume to the integral over its boundary:
As an example, let for a vector-valued function and a ()-grade multivector . We find that
A sufficiently smooth -surface in an -dimensional space is deemed a manifold. To each point on the manifold, we may attach a -blade that is tangent to the manifold. Locally, acts as a pseudoscalar of the -dimensional space. This blade defines a projection of vectors onto the manifold:
Just as the vector derivative is defined over the entire -dimensional space, we may wish to define an intrinsic derivative, locally defined on the manifold:
(Note: The right hand side of the above may not lie in the tangent space to the manifold. Therefore, it is not the same as , which necessarily does lie in the tangent space.)
If is a vector tangent to the manifold, then indeed both the vector derivative and intrinsic derivative give the same directional derivative:
Although this operation is perfectly valid, it is not always useful because itself is not necessarily on the manifold. Therefore, we define the covariant derivative to be the forced projection of the intrinsic derivative back onto the manifold:
Since any general multivector can be expressed as a sum of a projection and a rejection, in this case
we introduce a new function, the shape tensor, which satisfies
where is the commutator product. In a local coordinate basis spanning the tangent surface, the shape tensor is given by
Importantly, on a general manifold, the covariant derivative does not commute. In particular, the commutator is related to the shape tensor by
Clearly the term is of interest. However it, like the intrinsic derivative, is not necessarily on the manifold. Therefore, we can define the Riemann tensor to be the projection back onto the manifold:
Lastly, if is of grade , then we can define interior and exterior covariant derivatives as
We can alternatively introduce a -grade multivector as
and a measure
Apart from a subtle difference in meaning for the exterior product with respect to differential forms versus the exterior product with respect to vectors (in the former the increments are covectors, whereas in the latter they represent scalars), we see the correspondences of the differential form