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In mathematics, the Laplace operator or Laplacian is a differential operator given by the divergence of the gradient of a scalar function on Euclidean space. It is usually denoted by the symbols ${\displaystyle \nabla \cdot \nabla }$, ${\displaystyle \nabla ^{2))$ (where ${\displaystyle \nabla }$ is the nabla operator), or ${\displaystyle \Delta }$. In a Cartesian coordinate system, the Laplacian is given by the sum of second partial derivatives of the function with respect to each independent variable. In other coordinate systems, such as cylindrical and spherical coordinates, the Laplacian also has a useful form. Informally, the Laplacian Δf (p) of a function f at a point p measures by how much the average value of f over small spheres or balls centered at p deviates from f (p).

The Laplace operator is named after the French mathematician Pierre-Simon de Laplace (1749–1827), who first applied the operator to the study of celestial mechanics: the Laplacian of the gravitational potential due to a given mass density distribution is a constant multiple of that density distribution. Solutions of Laplace's equation Δf = 0 are called harmonic functions and represent the possible gravitational potentials in regions of vacuum.

The Laplacian occurs in many differential equations describing physical phenomena. Poisson's equation describes electric and gravitational potentials; the diffusion equation describes heat and fluid flow; the wave equation describes wave propagation; and the Schrödinger equation describes the wave function in quantum mechanics. In image processing and computer vision, the Laplacian operator has been used for various tasks, such as blob and edge detection. The Laplacian is the simplest elliptic operator and is at the core of Hodge theory as well as the results of de Rham cohomology.

Definition

The Laplace operator is a second-order differential operator in the n-dimensional Euclidean space, defined as the divergence (${\displaystyle \nabla \cdot }$) of the gradient (${\displaystyle \nabla f}$). Thus if ${\displaystyle f}$ is a twice-differentiable real-valued function, then the Laplacian of ${\displaystyle f}$ is the real-valued function defined by:

$${\displaystyle \Delta f=\nabla ^{2}f=\nabla \cdot \nabla f}$$

(1)

where the latter notations derive from formally writing:

$${\displaystyle \nabla =\left({\frac {\partial }{\partial x_{1))},\ldots ,{\frac {\partial }{\partial x_{n))}\right).}$$

$${\displaystyle \Delta f=\sum _{i=1}^{n}{\frac {\partial ^{2}f}{\partial x_{i}^{2))))$$

(2)

As a second-order differential operator, the Laplace operator maps C^k functions to C^k−2 functions for k ≥ 2. It is a linear operator Δ : C^k(Rⁿ) → C^k−2(Rⁿ), or more generally, an operator Δ : C^k(Ω) → C^k−2(Ω) for any open set Ω ⊆ Rⁿ.

Motivation

Diffusion

In the physical theory of diffusion, the Laplace operator arises naturally in the mathematical description of equilibrium.^[1] Specifically, if u is the density at equilibrium of some quantity such as a chemical concentration, then the net flux of u through the boundary ∂V of any smooth region V is zero, provided there is no source or sink within V:

$${\displaystyle \int _{\partial V}\nabla u\cdot \mathbf {n} \,dS=0,}$$

$${\displaystyle \int _{V}\operatorname {div} \nabla u\,dV=\int _{\partial V}\nabla u\cdot \mathbf {n} \,dS=0.}$$

Since this holds for all smooth regions V, one can show that it implies:

$${\displaystyle \operatorname {div} \nabla u=\Delta u=0.}$$

The Laplace operator itself has a physical interpretation for non-equilibrium diffusion as the extent to which a point represents a source or sink of chemical concentration, in a sense made precise by the diffusion equation. This interpretation of the Laplacian is also explained by the following fact about averages.

Averages

Given a twice continuously differentiable function ${\displaystyle f:\mathbb {R} ^{n}\to \mathbb {R} }$ and a point ${\displaystyle p\in \mathbb {R} ^{n))$. Then, the average value of ${\displaystyle f}$ over the ball with radius ${\displaystyle h}$ centered at ${\displaystyle p}$ is:^[2]

$${\displaystyle {\overline {f))_{B}(p,h)=f(p)+{\frac {\Delta f(p)}{2(n+2)))h^{2}+o(h^{2})\quad {\text{for))\;\;h\to 0}$$

Similarly, the average value of ${\displaystyle f}$ over the sphere (the boundary of a ball) with radius ${\displaystyle h}$ centered at ${\displaystyle p}$ is:

$${\displaystyle {\overline {f))_{S}(p,h)=f(p)+{\frac {\Delta f(p)}{2n))h^{2}+o(h^{2})\quad {\text{for))\;\;h\to 0.}$$

Density associated with a potential

If φ denotes the electrostatic potential associated to a charge distribution q, then the charge distribution itself is given by the negative of the Laplacian of φ:

$${\displaystyle q=-\varepsilon _{0}\Delta \varphi ,}$$

This is a consequence of Gauss's law. Indeed, if V is any smooth region with boundary ∂V, then by Gauss's law the flux of the electrostatic field E across the boundary is proportional to the charge enclosed:

$${\displaystyle \int _{\partial V}\mathbf {E} \cdot \mathbf {n} \,dS=\int _{V}\operatorname {div} \mathbf {E} \,dV={\frac {1}{\varepsilon _{0))}\int _{V}q\,dV.}$$

$${\displaystyle -\int _{V}\operatorname {div} (\operatorname {grad} \varphi )\,dV={\frac {1}{\varepsilon _{0))}\int _{V}q\,dV.}$$

Since this holds for all regions V, we must have

$${\displaystyle \operatorname {div} (\operatorname {grad} \varphi )=-{\frac {1}{\varepsilon _{0))}q}$$

The same approach implies that the negative of the Laplacian of the gravitational potential is the mass distribution. Often the charge (or mass) distribution are given, and the associated potential is unknown. Finding the potential function subject to suitable boundary conditions is equivalent to solving Poisson's equation.

Energy minimization

Another motivation for the Laplacian appearing in physics is that solutions to Δf = 0 in a region U are functions that make the Dirichlet energy functional stationary:

$${\displaystyle E(f)={\frac {1}{2))\int _{U}\lVert \nabla f\rVert ^{2}\,dx.}$$

To see this, suppose f : U → R is a function, and u : U → R is a function that vanishes on the boundary of U. Then:

$${\displaystyle \left.{\frac {d}{d\varepsilon ))\right|_{\varepsilon =0}E(f+\varepsilon u)=\int _{U}\nabla f\cdot \nabla u\,dx=-\int _{U}u\,\Delta f\,dx}$$

where the last equality follows using Green's first identity. This calculation shows that if Δf = 0, then E is stationary around f. Conversely, if E is stationary around f, then Δf = 0 by the fundamental lemma of calculus of variations.

Coordinate expressions

Two dimensions

The Laplace operator in two dimensions is given by:

In Cartesian coordinates,

$${\displaystyle \Delta f={\frac {\partial ^{2}f}{\partial x^{2))}+{\frac {\partial ^{2}f}{\partial y^{2))))$$

In polar coordinates,

$${\displaystyle {\begin{aligned}\Delta f&={\frac {1}{r)){\frac {\partial }{\partial r))\left(r{\frac {\partial f}{\partial r))\right)+{\frac {1}{r^{2))}{\frac {\partial ^{2}f}{\partial \theta ^{2))}\\&={\frac {\partial ^{2}f}{\partial r^{2))}+{\frac {1}{r)){\frac {\partial f}{\partial r))+{\frac {1}{r^{2))}{\frac {\partial ^{2}f}{\partial \theta ^{2))},\end{aligned))}$$

Three dimensions

In three dimensions, it is common to work with the Laplacian in a variety of different coordinate systems.

In Cartesian coordinates,

$${\displaystyle \Delta f={\frac {\partial ^{2}f}{\partial x^{2))}+{\frac {\partial ^{2}f}{\partial y^{2))}+{\frac {\partial ^{2}f}{\partial z^{2))}.}$$

In cylindrical coordinates,

$${\displaystyle \Delta f={\frac {1}{\rho )){\frac {\partial }{\partial \rho ))\left(\rho {\frac {\partial f}{\partial \rho ))\right)+{\frac {1}{\rho ^{2))}{\frac {\partial ^{2}f}{\partial \varphi ^{2))}+{\frac {\partial ^{2}f}{\partial z^{2))},}$$

${\displaystyle \rho }$

In spherical coordinates:

$${\displaystyle \Delta f={\frac {1}{r^{2))}{\frac {\partial }{\partial r))\left(r^{2}{\frac {\partial f}{\partial r))\right)+{\frac {1}{r^{2}\sin \theta )){\frac {\partial }{\partial \theta ))\left(\sin \theta {\frac {\partial f}{\partial \theta ))\right)+{\frac {1}{r^{2}\sin ^{2}\theta )){\frac {\partial ^{2}f}{\partial \varphi ^{2))},}$$

$${\displaystyle \Delta f={\frac {1}{r)){\frac {\partial ^{2)){\partial r^{2))}(rf)+{\frac {1}{r^{2}\sin \theta )){\frac {\partial }{\partial \theta ))\left(\sin \theta {\frac {\partial f}{\partial \theta ))\right)+{\frac {1}{r^{2}\sin ^{2}\theta )){\frac {\partial ^{2}f}{\partial \varphi ^{2))},}$$

$${\displaystyle \Delta f={\frac {\partial ^{2}f}{\partial r^{2))}+{\frac {2}{r)){\frac {\partial f}{\partial r))+{\frac {1}{r^{2}\sin \theta )){\frac {\partial }{\partial \theta ))\left(\sin \theta {\frac {\partial f}{\partial \theta ))\right)+{\frac {1}{r^{2}\sin ^{2}\theta )){\frac {\partial ^{2}f}{\partial \varphi ^{2))},}$$

In general curvilinear coordinates (ξ¹, ξ², ξ³):

$${\displaystyle \Delta =\nabla \xi ^{m}\cdot \nabla \xi ^{n}{\frac {\partial ^{2)){\partial \xi ^{m}\,\partial \xi ^{n))}+\nabla ^{2}\xi ^{m}{\frac {\partial }{\partial \xi ^{m))}=g^{mn}\left({\frac {\partial ^{2)){\partial \xi ^{m}\,\partial \xi ^{n))}-\Gamma _{mn}^{l}{\frac {\partial }{\partial \xi ^{l))}\right),}$$

where summation over the repeated indices is implied, g^mn is the inverse metric tensor and Γ^l _mn are the Christoffel symbols for the selected coordinates.

N dimensions

In arbitrary curvilinear coordinates in N dimensions (ξ¹, ..., ξ^N), we can write the Laplacian in terms of the inverse metric tensor, ${\displaystyle g^{ij))$:

$${\displaystyle \Delta ={\frac {1}{\sqrt {\det g))}{\frac {\partial }{\partial \xi ^{i))}\left({\sqrt {\det g))g^{ij}{\frac {\partial }{\partial \xi ^{j))}\right),}$$

In spherical coordinates in N dimensions, with the parametrization x = rθ ∈ R^N with r representing a positive real radius and θ an element of the unit sphere S^N−1,

$${\displaystyle \Delta f={\frac {\partial ^{2}f}{\partial r^{2))}+{\frac {N-1}{r)){\frac {\partial f}{\partial r))+{\frac {1}{r^{2))}\Delta _{S^{N-1))f}$$

$${\displaystyle {\frac {1}{r^{N-1))}{\frac {\partial }{\partial r))\left(r^{N-1}{\frac {\partial f}{\partial r))\right).}$$

As a consequence, the spherical Laplacian of a function defined on S^N−1 ⊂ R^N can be computed as the ordinary Laplacian of the function extended to R^N∖{0} so that it is constant along rays, i.e., homogeneous of degree zero.

Euclidean invariance

The Laplacian is invariant under all Euclidean transformations: rotations and translations. In two dimensions, for example, this means that:

$${\displaystyle \Delta (f(x\cos \theta -y\sin \theta +a,x\sin \theta +y\cos \theta +b))=(\Delta f)(x\cos \theta -y\sin \theta +a,x\sin \theta +y\cos \theta +b)}$$

$${\displaystyle \Delta (f\circ \rho )=(\Delta f)\circ \rho }$$

$${\displaystyle \Delta (f\circ \tau )=(\Delta f)\circ \tau }$$

In fact, the algebra of all scalar linear differential operators, with constant coefficients, that commute with all Euclidean transformations, is the polynomial algebra generated by the Laplace operator.

Spectral theory

The spectrum of the Laplace operator consists of all eigenvalues λ for which there is a corresponding eigenfunction f with:

$${\displaystyle -\Delta f=\lambda f.}$$

This is known as the Helmholtz equation.

If Ω is a bounded domain in Rⁿ, then the eigenfunctions of the Laplacian are an orthonormal basis for the Hilbert space L²(Ω). This result essentially follows from the spectral theorem on compact self-adjoint operators, applied to the inverse of the Laplacian (which is compact, by the Poincaré inequality and the Rellich–Kondrachov theorem).^[4] It can also be shown that the eigenfunctions are infinitely differentiable functions.^[5] More generally, these results hold for the Laplace–Beltrami operator on any compact Riemannian manifold with boundary, or indeed for the Dirichlet eigenvalue problem of any elliptic operator with smooth coefficients on a bounded domain. When Ω is the n-sphere, the eigenfunctions of the Laplacian are the spherical harmonics.

Vector Laplacian

The vector Laplace operator, also denoted by ${\displaystyle \nabla ^{2))$, is a differential operator defined over a vector field.^[6] The vector Laplacian is similar to the scalar Laplacian; whereas the scalar Laplacian applies to a scalar field and returns a scalar quantity, the vector Laplacian applies to a vector field, returning a vector quantity. When computed in orthonormal Cartesian coordinates, the returned vector field is equal to the vector field of the scalar Laplacian applied to each vector component.

The vector Laplacian of a vector field ${\displaystyle \mathbf {A} }$ is defined as

$${\displaystyle \nabla ^{2}\mathbf {A} =\nabla (\nabla \cdot \mathbf {A} )-\nabla \times (\nabla \times \mathbf {A} ).}$$

In Cartesian coordinates, this reduces to the much simpler form as

$${\displaystyle \nabla ^{2}\mathbf {A} =(\nabla ^{2}A_{x},\nabla ^{2}A_{y},\nabla ^{2}A_{z}),}$$

${\displaystyle A_{x))$

${\displaystyle A_{y))$

${\displaystyle A_{z))$

${\displaystyle \mathbf {A} }$

${\displaystyle \nabla ^{2))$

For expressions of the vector Laplacian in other coordinate systems see Del in cylindrical and spherical coordinates.

Generalization

The Laplacian of any tensor field ${\displaystyle \mathbf {T} }$ ("tensor" includes scalar and vector) is defined as the divergence of the gradient of the tensor:

$${\displaystyle \nabla ^{2}\mathbf {T} =(\nabla \cdot \nabla )\mathbf {T} .}$$

For the special case where ${\displaystyle \mathbf {T} }$ is a scalar (a tensor of degree zero), the Laplacian takes on the familiar form.

If ${\displaystyle \mathbf {T} }$ is a vector (a tensor of first degree), the gradient is a covariant derivative which results in a tensor of second degree, and the divergence of this is again a vector. The formula for the vector Laplacian above may be used to avoid tensor math and may be shown to be equivalent to the divergence of the Jacobian matrix shown below for the gradient of a vector:

$${\displaystyle \nabla \mathbf {T} =(\nabla T_{x},\nabla T_{y},\nabla T_{z})={\begin{bmatrix}T_{xx}&T_{xy}&T_{xz}\\T_{yx}&T_{yy}&T_{yz}\\T_{zx}&T_{zy}&T_{zz}\end{bmatrix)),{\text{ where ))T_{uv}\equiv {\frac {\partial T_{u)){\partial v)).}$$

And, in the same manner, a dot product, which evaluates to a vector, of a vector by the gradient of another vector (a tensor of 2nd degree) can be seen as a product of matrices:

$${\displaystyle \mathbf {A} \cdot \nabla \mathbf {B} ={\begin{bmatrix}A_{x}&A_{y}&A_{z}\end{bmatrix))\nabla \mathbf {B} ={\begin{bmatrix}\mathbf {A} \cdot \nabla B_{x}&\mathbf {A} \cdot \nabla B_{y}&\mathbf {A} \cdot \nabla B_{z}\end{bmatrix)).}$$

Use in physics

An example of the usage of the vector Laplacian is the Navier-Stokes equations for a Newtonian incompressible flow:

$${\displaystyle \rho \left({\frac {\partial \mathbf {v} }{\partial t))+(\mathbf {v} \cdot \nabla )\mathbf {v} \right)=\rho \mathbf {f} -\nabla p+\mu \left(\nabla ^{2}\mathbf {v} \right),}$$

${\displaystyle \mu \left(\nabla ^{2}\mathbf {v} \right)}$

Another example is the wave equation for the electric field that can be derived from Maxwell's equations in the absence of charges and currents:

$${\displaystyle \nabla ^{2}\mathbf {E} -\mu _{0}\epsilon _{0}{\frac {\partial ^{2}\mathbf {E} }{\partial t^{2))}=0.}$$

This equation can also be written as:

$${\displaystyle \Box \,\mathbf {E} =0,}$$

$${\displaystyle \Box \equiv {\frac {1}{c^{2))}{\frac {\partial ^{2)){\partial t^{2))}-\nabla ^{2},}$$

Generalizations

A version of the Laplacian can be defined wherever the Dirichlet energy functional makes sense, which is the theory of Dirichlet forms. For spaces with additional structure, one can give more explicit descriptions of the Laplacian, as follows.

Laplace–Beltrami operator

The Laplacian also can be generalized to an elliptic operator called the Laplace–Beltrami operator defined on a Riemannian manifold. The Laplace–Beltrami operator, when applied to a function, is the trace (tr) of the function's Hessian:

$${\displaystyle \Delta f=\operatorname {tr} {\big (}H(f){\big )))$$

Another generalization of the Laplace operator that is available on pseudo-Riemannian manifolds uses the exterior derivative, in terms of which the "geometer's Laplacian" is expressed as

$${\displaystyle \Delta f=\delta df.}$$

Here δ is the codifferential, which can also be expressed in terms of the Hodge star and the exterior derivative. This operator differs in sign from the "analyst's Laplacian" defined above. More generally, the "Hodge" Laplacian is defined on differential forms α by

$${\displaystyle \Delta \alpha =\delta d\alpha +d\delta \alpha .}$$

This is known as the Laplace–de Rham operator, which is related to the Laplace–Beltrami operator by the Weitzenböck identity.

D'Alembertian

The Laplacian can be generalized in certain ways to non-Euclidean spaces, where it may be elliptic, hyperbolic, or ultrahyperbolic.

In Minkowski space the Laplace–Beltrami operator becomes the D'Alembert operator ${\displaystyle \Box }$ or D'Alembertian:

$${\displaystyle \square ={\frac {1}{c^{2))}{\frac {\partial ^{2)){\partial t^{2))}-{\frac {\partial ^{2)){\partial x^{2))}-{\frac {\partial ^{2)){\partial y^{2))}-{\frac {\partial ^{2)){\partial z^{2))}.}$$

It is the generalization of the Laplace operator in the sense that it is the differential operator which is invariant under the isometry group of the underlying space and it reduces to the Laplace operator if restricted to time-independent functions. The overall sign of the metric here is chosen such that the spatial parts of the operator admit a negative sign, which is the usual convention in high-energy particle physics. The D'Alembert operator is also known as the wave operator because it is the differential operator appearing in the wave equations, and it is also part of the Klein–Gordon equation, which reduces to the wave equation in the massless case.

The additional factor of c in the metric is needed in physics if space and time are measured in different units; a similar factor would be required if, for example, the x direction were measured in meters while the y direction were measured in centimeters. Indeed, theoretical physicists usually work in units such that c = 1 in order to simplify the equation.

The d'Alembert operator generalizes to a hyperbolic operator on pseudo-Riemannian manifolds.