Amaua
Village
Amaua is located in American Samoa
Amaua
Amaua
Coordinates: 14°16′37″S 170°37′18″W / 14.27694°S 170.62167°W / -14.27694; -170.62167Coordinates: 14°16′37″S 170°37′18″W / 14.27694°S 170.62167°W / -14.27694; -170.62167
Country United States
Territory American Samoa
CountySua
Area
 • Total0.33 sq mi (0.86 km2)
Elevation
92 ft (28 m)
Population
 (2010)
 • Total96
 • Density290/sq mi (110/km2)
Time zoneUTC−11 (Samoa Time Zone)
ZIP code
96799
Area code(s)+1 684

Amaua is a village in the southeast of Tutuila Island, American Samoa. It is located on the north shore of Faga'itua Bay between Alega and Faga'itua.

Amaua's mayor, Pulenu'u Troy Fia-ui, was taken into custody by the police in January 2011 after marijuana plants were discovered by his home.[1][2]

As of 2010, Amaua had a 94.8 high school graduation percent, which was among the highest recorded of any village in American Samoa.[3]

Demographics

Population growth[4]
2010 96
2000 102
1990 128
1980 90

References

  1. ^ "American Samoa village official arrested on drug charges". 19 January 2011.
  2. ^ "American Samoa mayor in drugs probe". 18 January 2011.
  3. ^ http://doc.as.gov/wp-content/uploads/2011/06/American-Samoa-Statistical-Yearbook-2016.pdf Archived 2019-02-14 at the Wayback Machine (Page 60)
  4. ^ "American Samoa Statistical Yearbook 2016" (PDF). American Samoa Department of Commerce. Archived from the original (PDF) on 2019-02-14. Retrieved 2019-07-25.